(2x/x-3)-(6/x)=18/(x^2-3x)

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Solution for (2x/x-3)-(6/x)=18/(x^2-3x) equation: 



(2x/x-3)-(6/x)=18/(x^2-3x)

We move all terms to the left:

(2x/x-3)-(6/x)-(18/(x^2-3x))=0



Domain of the equation: x-3)!=0

x∈R





Domain of the equation: x)!=0

x!=0/1

x!=0

x∈R





Domain of the equation: (x^2-3x))!=0

x∈R



We add all the numbers together, and all the variables

(2x/x-3)-(+6/x)-(18/(x^2-3x))=0

We get rid of parentheses

2x/x-6/x-(18/(x^2-3x))-3=0

We calculate fractions

We do not support expression: x^3

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